How to call a public method in php through object literals?

Question

PHP

class A {
  public function a() {
    echo "a";
  }
}

class B extends A {
  public function controll($method) {
    $methods = [
      "returnA" => $this -> a()
    ]; return $methods[$method];
  }
}

$b = new B;
$b -> controll("returnA");

So the question is:
This will only work if there is only one method in $methods, if there are more, then they are called immediately after the array is initialized. How to make it so that you can call them only when necessary, without using switch and conditional statements.

Answer 1

you can use __invoke()

public function __invoke($method)
{
     $methods = get_class_methods(static::class);
      if (!in_array($method, $methods)) {
            throw new BadMethodCallException($method);
      }
      return [$this, $method]();
}

well and use: $instance = new Test(); $instance($method);

Answer 2

If I understand you correctly, you can do something like this

<?php
class A
{
    public function a()
    {
        echo "a";
    }
}

class B extends A
{
    public function controll($method)
    {
        if (method_exists($this, $method)) { // проверяем существует ли метод
            $reflectionMethod  = new ReflectionMethod($this, $method);
            if ($reflectionMethod->isPublic()) { // проверка является ли метод публичным
                return $this->$method(); // вызываем функцию
            }
        }
    }
}

$b = new B;
$b->controll("a");