How to call a function that is in the body of another function?

Question

Python

Let's say I have a program:

def foo():
    # code
    def foo_in_foo():
        # code

How can you call the function foo_in_foo in the outer area of ​​the code?

# что-то вроде того:
foo.foo_in_foo()

Answer 1

No way. You can't access a function's local variable, which is essentially the same thing.

Answer 2

Why not, you can pull it out through a global variable.
Just don't remember this approach, it's terrible code:

>>> def foo():
... 	print('executing foo()')
... 	def foo_in_foo():
... 		print('executing foo_in_foo()')
... 	global inner
... 	inner = foo_in_foo
... 
>>> foo()
executing foo()
>>> inner
<function foo.<locals>.foo_in_foo at 0x07BBD1E0>
>>> inner()
executing foo_in_foo()

Answer 3

You can do it, but you don't have to

>>> def foo():
...     print('in foo')
...     def foo_in_foo():
...         print('in foo_in_foo')
...     foo.foo_in_foo = foo_in_foo
... 
>>> foo()
in foo
>>> foo.foo_in_foo()
in foo_in_foo
>>>