How to calculate the sum of numbers in a file?

Question

PHP

char buff[11]; 
float a=0;
        ofstream file;
  file.open("C:/Users/Desktop/test.txt");
  file << "0123456789";
  file.close(); //создал, открыл, записал, закрыл

  ifstream fin("C:/Users/Desktop/test.txt"); // открыл для чтения

  fin >> buff; // считали первое слово из файла
  cout << buff; // напечатали это слово

  fin.getline(buff, 11); // считали строку из файла
  fin.close(); // закрываем файл
   for (int i = 0; i < 11; i++){
    a +=  buff[i];
    cout << buff[i] << "\t" << a << endl;
  }

How to count them, how to write them into variables? "a" prints complete nonsense, large numbers. How to work with them?

Answer 1

make a function call in the file

<?
test($_GET['a']);
?>

Answer 2

php.net/manual/en/reserved.variables.get.php

Answer 3

I don’t remember that in php there was once such a way to call functions via a GET request.
Here, access to parameters like test.php?a=123 was once possible through $a, now it is better to use $_GET{'a'} for this (and even better - then check the passed value for validity).
If you want to call several different functions - call test.php?func=test¶m=123 and in your code already do if ($_GET{'func'} == 'test') { test($_GET{'param'}); } and so on like that.

Answer 4

So far I see this.
1. a += buff[i];You are summing character codes, not their numerical values. Correct a += buff[i] - '0';
2. These lines duplicate each other.

fin >> buff;
  fin.getline(buff, 11);

First we get 0123456789, then the file is over and in place 0 we write the null character (NUL).
3. for (int i = 0; i < 11; i++)- non-universal design. There are only 10 plus numbers in the line, so you need i < 10.
4. So the sum of numbers or the sum of digits?