How to calculate the force of impact on point A?

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blajlhimik2021-07-01 13:44:14

Physics

blajlhimik, 2021-07-01 13:44:14

How can the force on point A be calculated? I think that there is no need for a corner, but just in case. Length from point A to moving element = dN. xB is the point of impact with some force 50N(5kg) for example.

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2 answer(s)

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Vindicar, 2021-07-01
@Vindicar

Well, if you think logically.
If dM = 0, then xA must be equal to xB.
The larger dM, the more xA differs from xB.
If dM = -dN, then xA must be 0.
If the lever is not deformed and is stationary, then the proportion suggests itself, based on the equality of angular momentum:
dN * xA = (dN + dM) * xB
Hence xA = xB * (dN + dM ) / dN

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Vitaly Kachan, 2021-07-02
@MANAB

Do I understand correctly that the strength in xB is already known? And point A is the attachment point? Then, in theory, the force transfer rule should work, and the force of impact on point A is equal to the sum of the gravity forces of the load and the force applied to point B * cos of the angle between the force vector at point B and the vertical axis of attachment.
If the force in xB must be calculated, then what is the condition? Equilibrium?