How to build a plugin only from the required modules?

Question

npm

Hello guys!
Please explain to the dumb one...

I have a project that I build using gulp. I set everything up according to the article: https://habr.com/ru/post/484714/
Everything works fine.

But here I decided to use the plugin https://swiperjs.com/get-started/
in the js project And as I understand it, this plugin consists of a core and many other modules that I don’t need in the code.

The question is, how can I assemble the plugin in the required configuration and connect it to the project?

JS is built like this:

const gulp = require('gulp');
const concat = require('gulp-concat');
const babel = require('gulp-babel');
const terser = require('gulp-terser');
const rename = require('gulp-rename');
const sourcemaps = require('gulp-sourcemaps');

module.exports = function script(cb) {
    return gulp.src([
        'node_modules/jquery/dist/jquery.min.js',
        'src/scripts/keengo.moreNav.js',
        'src/scripts/autocomplete.js',
        'src/scripts/perfectscroll.js',
        'src/scripts/scripts.js'
    ])
        .pipe(sourcemaps.init())
        .pipe(babel({
            presets: ['@babel/env']
        }))
        .pipe(concat('scripts.js')) // Конкатенируем в один файл
        .pipe(terser())
        .pipe(sourcemaps.write())
        .pipe(rename({suffix: '.min'}))
        .pipe(gulp.dest('build/js'));
};

Thank you!
do not scold too much for a stupid question)