How to avoid 403 response?

Question

Python

So far the code has worked fine. Now returns a 403 response
. Does anyone know how to fix it?

import requests
import json


def main():
  ids = [4570694029, 3203317426, 4546274771, 4611188675]
  for i in ids:
    url = 'https://api.domofond.ru/rpc'
    data = {"id":"1", "jsonrpc":"2.0", "method":"item.GetItemPhoneV1", "params":{"meta":{"platform":"web","language":"ru"},"id":i,"itemType":"Listing"}}
    data = json.dumps(data)
    headers={"Host": "api.domofond.ru",
        "User-Agent": "Mozilla/5.0",
        "Accept": "*/*",
        "Accept-Language": "ru-RU,ru;q=0.8,en-US;q=0.5,en;q=0.3",
        "Accept-Encoding": "gzip, deflate, br",
        "Referer": "https://www.domofond.ru/2-komnatnaya-kvartira-na-prodazhu-sankt_peterburg-4611188675",
        "Content-Type": "text/plain",
        "X-Request-Id": "b04f3c5b-378a-45fc-b382-0c88d2c885bd",
        "Origin": "https://www.domofond.ru",
        "Content-Length": "147",
        "Connection": "keep-alive",
        "Cookie": "dfuid=4952dc07-cedd-4723-8825-692441fd1677; _ga=GA1.2.207709362.1630835300; rrpvid=988184375939883; rcuid=61349266c783820001ac3e67; duid=xndoXW0qrC64ZSjlXXSSl7JFtUv0awhLYlj24MLfWfjl4tio; _gid=GA1.2.809471283.1643743940; cto_bundle=6iKxGl9SQ3U3dFJPQzJDWnJlTmtXclg5MlJEUFRsJTJCUyUyRmxPZGtFdyUyQiUyQmhLNlJRSTFyMHRGeUtISSUyQnlRVkpvVFNSOEROY1dlemtGQXNsMlN1eUU0TmtTcDZKZlZicU12QmRBZGJrRnpzb2pNRVJROWhpSFlZV2Q2WjZxYUtwNGNOUTJyaVNIN3FzbTExREpQZkFOTGo4ZUx5JTJGTVElM0QlM0Q; rr-viewItemId=2330241172; rrviewed=2322634746%2C2103317227%2C2308774220%2C2330241172; rrlevt=1643744013897",
        "TE": "Trailers",
        "Pragma": "no-cache",
        "Cache-Control": "no-cache"}
    r = requests.post(url, data=data, headers=headers)
    print(r.json)
    # json_string = json.loads(r.text)
    print(json_string['result']['phone'])
if __name__ == '__main__':
  main()