How to automatically respond to the interlocutor in Python + vk api when receiving a new letter?

Question

Python

Greetings, in general, I drank all the sedatives that were in the house and my legs hurt from squats
, there is a piece of code where I log in and then I need to track the appearance of a new letter, I use messages.getDialogs with parameters count=20 and unread=1 but when I run this I get a mat from ide in the form vk.exceptions.VkAPIError: 100.

import vk

session = vk.AuthSession(
                        'app_id',
                        'login',
                        'pass',
                        scope='messages'
                        )
vk_api = vk.API(session)

massages=vk_api.messages.getDialogs(count=20, unread=1)

print(massages)

Answer 1

import vk
import time
import requests as req
from lxml import html

app_id, login, password = 'app_id', '[email protected]', 'password'
session = vk.AuthSession(app_id, login, password, scope='messages')
vk_api = vk.API(session, v='5.62')

while True:
    massages=vk_api.messages.getDialogs(count=20, unread=1)
   
    if massages['count']==1:
        print('Новое письмо', massages)
        id = massages['items'][0]['message']['user_id']
        body=massages['items'][0]['message']['body']
        print(id, body)
        if body=='bash':
            r = req.get('http://bash.im/random')
            doc = html.document_fromstring(r.text)
            bash = '\n'.join(doc.xpath('//*[@id="body"]/div[3]/div[@class="text"]/text()'))
            vk_api.messages.send(user_id=id, message=bash)
            print()
        else:
            vk_api.messages.send(user_id=id, message='Если вы введете "bash" то я вышлю вам цитату с bash.im')
    elif massages['count']==0:
        print('Новых писем нет')
    time.sleep(1)

thanks for the hint with the prawn-cake version

Answer 2

Try https://github.com/prawn-cake/vk-requests
The out-of-the-box library handles a lot of cases and it has fixed a lot of bugs compared to vk. Well, she is also python 3 compatible.
In the case of replying to messages, for example, it might look like this

api = vk_requests.create_api(app_id=123, login='User', password='Password', scope=['offline', 'messages'])
messages = api.messages.getDialogs(count=20, unread=1)

for msg in messages['items']:
    api.messages.send(peer_id=msg['user_id'], message='Hello world')

Answer 3

Using frequent requests of the same type to the VK API will, at best, manage to ignore these requests.
In your case, it is better to use this method for private messages - https://vk.com/dev/messages.getLongPollServer.
In case of messages to the community - https://vk.com/dev/callback_api.

Answer 4

2 == "2" //true
2 === "2" //false

Answer 5

Ordinary equality and strict