How does this remove method work?

Question

Java

package main;

public class MyArrayList {
    private String[] array = new String[10];
    private int size = 0;

    public void remove(int index) {
        if (index >= 0 && index < size) {
            for (int i = index; i < array.length - 1; i++) {
                array[i] = array[i + 1];
            }
            size--;
        }
    }
    public void add(String s) {
        array[size] = s;
        size++;
        if (size == array.length) {
            String[] newArray = new String[array.length * 2];
            for (int i = 0; i < array.length; i++) {
                newArray[i] = array[i];
            }
            array = newArray;
        }
    }


}

The principle of operation seems to be clear - the method assigns the value of the next element to the current element. But it turns out that if the penultimate element is assigned the value of the last one and the method stops working on this, then the last element and the penultimate one will have the same values?

Answer 1

Well, yes, it will, but the last element will no longer need to be looked at, due to the fact that size is there, this is the logical size of this container.
And there is extra work going on in the for loop. i < array.length - 1, which should be < size.