How does the Ruby interpreter work?

Question

ruby

As you know, in Ruby, <=>, [], + and other "operations" are methods that can be overridden.
How does the interpreter understand that methodparameters can be passed to using method(params), and in the case of the [] method, it "understands" that the parameters are between square brackets and round brackets can no longer be used. Similarly, how does one parse that method = 1 is the same as method= 1?
Where is the best place to read more about such details? How much sugar of this kind is in the tongue?

Answer 1

This is defined by the ruby ​​syntax and is not changeable.
In more detail, first the source text is parsed into an intermediate representation of the code. After that, individual characters '[' and ']' cease to exist, the code becomes a tree structure in memory, which already stores entire operators in nodes. And accordingly, by redefining the :[] operator, you really just shuffle the pointers in this structure, which knows nothing about the syntax of the input language (in our case, ruby)

Answer 2

Probably here, only C will have to be learned =)
https://github.com/ruby/ruby/blob/trunk/method.h

Answer 3

It all collapses at runtime. That is, until the moment the function (operator) is directly called, it is not known what exactly will be called. The analysis of the source codes, I dare to assume, is organized, like everyone else, by means of AST.

Answer 4

mb late binding mechanism?