How does the field become current?

Question

Electronics

How, when the circuit with the coil is opened, does its electromagnetic field turn into a current? Correct if something is wrong. I am newbie

Answer 1

Apparently, we are talking about self-induction . If we draw an analogy with water, then we can imagine it like this: water moves through a pipe at high speed (this is a current ). In this case, there is no pressure in the pipe or it is minimal (this is stress ). If you abruptly close the path to the water (break the circuit), then the dispersed water has nowhere to go and it is "tamped down", creating pressure ( raises voltage ).
And if you do not go into simplifications, then when the circuit with the coil is opened, the
current in the coil begins to decrease,
the magnetic field decreases,
the alternating magnetic field generates a vortex electric field
that entrains charge carriers,
which generate an induced current.
Everything happens according to Le Chatelier's principle - a system that is out of balance tends to its previous state.

Answer 2

When the circuit with the coil is opened (i.e., when the current through the coil changes), an EMF of self-induction occurs, google "electromagnetic induction" for more details. If you really want to understand the issue, you will have to read a textbook on electrodynamics, this cannot be explained in a nutshell.

Answer 3

>How, when the circuit with the coil is opened, does its electromagnetic field turn into a current?
Actually current - was there before opening. So this current (kinetic - I don’t know the correct term - energy) goes into an electric field (potential energy), in other words - voltage.
> Correct me if I'm wrong.
So it is not clear what version you put forward, Padawan.