How does the compiler run tasks in a for loop at the same time?

Question

Java

Hello!
Let's say there is a code:

ExecutorService exec = Executors.newThreadCachedPool();
for(int i = 0; i < 10; i++)
    exec.execute(new SomeRunnable());

How does the compiler run all 10 tasks at the same time, if, as I understand it, the for loop is a sequential iteration from the 0th to the 9th element; therefore, there must be some delay between threads starting (especially between the first and the last). How is it even possible to write multi-threaded code within a code if the code itself is a kind of sequential algorithm of commands? Got confused a little.
Thank you.

Answer 1

It does not start the compiler, but the runtime, and the ExecutorService starts each process in its own asynchronous thread. There is a delay between iterations in the loop, but it can be taken almost equal to zero. By the way, still Executors.newCachedThreadPool() .

Answer 2

First, the compiler does not run anything, but only compiles the program.
Secondly, the tasks do not run simultaneously, but sequentially, as you expected. But since tasks are started on a new thread, the program does not wait for them to complete before starting the next one.
There is a delay between launches, but it is insignificant.

Answer 3

1) The compiler does not run anything from your code at all.
2) Well, how. I created a thread, the thread works separately - the cycle went further. The delay is stupid for creating a thread, but not for its execution logic.
Yes. Within a single thread, this is true. But within a few, no.