How does ShellExecute work, can't set working folder?

Question

Delphi

My main program starts program_1 using the ShellExecute method.

ShellExecute(Handle, 'open', 'control\Project1.exe', nil, nil, SW_HIDE);

Program_1, in turn, should open the .txt file. But she does not open it because it is not clear how to set the working folder in the method correctly.

Answer 1

shellexecute has so many options. Point to the method and see. I hope you can guess that Directory is the working directory