How does Scanner scanner work as a method parameter?

Question

Java

Good afternoon. There is a problem on code decomposition. Spaghetti should be removed from the main method and scattered over other methods. One of them looks like this:

public static void convert(Scanner scanner, double moneyBeforeSalary) {
        
        double rateUSD = 78.5;
        double rateEUR = 85;
        double rateJPY = 0.74;
        
        System.out.println("Ваши сбережения: " + moneyBeforeSalary + " RUB");
        System.out.println("В какую валюту хотите конвертировать? Доступные варианты: 1 - USD, 2 - EUR, 3 - JPY.");
        int currency = scanner.nextInt();
        
        if (currency == 1) {
            System.out.println("Ваши сбережения в долларах: " + moneyBeforeSalary / rateUSD);
        } else if (currency == 2) {
            System.out.println("Ваши сбережения в евро: " + moneyBeforeSalary / rateEUR);
        } else if (currency == 3) {
            System.out.println("Ваши сбережения в иенах: " + moneyBeforeSalary / rateJPY);
        } else {
            System.out.println("Неизвестная валюта");
        }
    }

The task statement says:

The convert method will be used to convert currencies. You will find the parameters for it in the precode. It should take as arguments the balance of the account and a variable of complex type scanner - this will avoid duplicating the code for reading the currency selection.

I don't understand how the Scanner scanner should work here, and what should be passed in its place when calling the method.

Question: how to change the code so that it is correct, and how to correctly call the method so that it works?

Thanks in advance!

Answer 1

The Scanner object is simply passed to the method, see where it reads from.
You can pass system input like this:
convert(new Scanner(System.in), 1.55)