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How does current flow in parallel?
If you solder 2 fuses in parallel in a circuit, so that there is more tin at the ends of one of them, will more current go there, or will it be divided by exactly 2 anyway?
And the second case: if you use 2 different fuses (one for 30A and the other for 20A). The question is still the same.
Please explain your answer.
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Current through parallel branches will flow in strict accordance with Ohm's law, i.e. where the resistance of the branch is less, there is more current through it. The voltage is the same on them, so there is no other reason for the difference in currents. Therefore, it is absolutely impossible
to do as you described in the example with fuses . Those who think that the fuse current is summed up are completely mistaken, and the reason for this is the spread of parameters. No two parts are exactly alike, and fuses are no exception. Therefore, if you parallelize two supposedly identical ones, and then increase the current through them, then the one with a little less resistance will burn out first, and then, left alone, the second one will burn out in a matter of milliseconds.
The same will happen in your second case - a bunch of 20 + 30 will burn out not at 50, but at (conditionally) 30 amperes. Conditionally - because the actual combustion current depends on many factors and therefore has a very large spread even for a single fuse, and even more so for parallel fuses.
The current will flow according to the resistance of the conductors. It depends on how they soldered, depending on what resistance the fuses have. If they are generally made using the same technology, and the soldering is ideal, then it almost does not depend on the amount of tin and will be divided approximately equally.
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