How can I put all parameters into an object while iterating over an array?

Question

Python

I want to shove several parameters into an object that are in an array

class obj(object):
    def __init__(
        self, 
        text='white',
        background='white'
    ):
        print('{}-{}'.format(
            text,
            background
        ))
        # Дальше идет куча другого кода...


def fun(**kwargs) :
    for x in range(2) :
        for key, value in kwargs.items():
            #obj(**kwargs)
            if key == 'text' :
                obj(key=value[x+1])
            else:
                obj(key=value[x])

fun(
    text=[
        'red',
        'blue',
        'green'
    ],
    background=[
        'black',
        'yellow',
        'brown'
    ]
)

fun()

Each fun() function should only generate 2 objects

1
blue-black
green-yellow
2
white-black
white-black

I would like to leave the ability to somehow influence the index of the arrays of each of the parameters separately.
And I would like to avoid using try and extra if else

Answer 1

Can you explain your task properly? There are no arrays in the code at all, only linear lists.

put multiple parameters into an object

what???? And at least observe pep8 a little, please.

Answer 2

obj is an object. It's not an instance of an object, so there's no way you can do it
See OOP Principles

Answer 3

def fun(**kwargs) :
  for x in range(2) :
    #obj(**kwargs)
    text = kwargs['text'][x+1]
    background = kwargs['background'][x]
    obj(text, background)

But in general, as in the previous question, the implementation methods you have chosen look pretty wild.