How can I pass nothing to the function so that the default value would work?

Question

Python

I'm just learning python so I don't know if it's possible to pass an empty to a function so that the default value would work. After all, I have two functions where one passes a value to the other, and in order not to write the default value twice, is it possible to write an empty one.

Is there such a value in python?

Using if else is not suitable because if there are several variables, then you have to write all combinations.

def test_1(arr_1=[1,232,1134,134,1113,442,23,1134,313,4,5232,533,32], arr_2=[393,399,23009,11999,309,399,9]):
  #Просто выводит либо значения по умолчанию либо то что в него передали неважно что
  print("{}-{}".format(arr_1,arr_2))
  
def test_2(val_1=None,val_2=None):
  #сокращенно
  test_1(val_1,val_2)
  
  #C использованием if else
  if val_1== None and val_2==None:
    test_1()
  elif val_1== None and not val_2==None:
    test_1(arr_2=val_2)
  elif val_2== None and not val_1==None:
    test_1(val_1)
    
  # Дальше исполняет что то
  
test_1()
test_2()
test_2('f')
test_2('f','D')
test_2(val_2='D')

The test_1 function cannot be edited in any way, as it can be used in different parts of the code.

Answer 1

*args, **kwargs

def test_1(val_1=(1, 232, 1134), val_2=(393, 399, 23009)):
    print("{}-{}".format(val_1, val_2))


def test_2(*args, **kwargs):
    test_1(*args, **kwargs)


test_2()
test_2('f')
test_2('f', 'D')
test_2(val_2='D')