How can I make it so that when I click on an item in the ListView, a dialog opens with the information I need?

Question

Java

Good day to all!
Being completely green in Android development, I encountered a problem for which I could not find a solution on the Internet ( If you still have a link or a ready-made solution, I will be grateful. ).
There is a string array with the name of coffee drinks, which is passed to the ListView .
By clicking on the element, an AlertDialog opens , and in it I want to pass the composition of these drinks.
Here is the code:

spoiler

public class MainActivity extends AppCompatActivity {

    final Context context = this;
    ListView listView;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        listView = (ListView) findViewById(R.id.listView);//листвью

        final String[] values = new String[]
                {"Americano", "Cappuccino", "Latte"};//строковый массив

        ArrayAdapter adapter = new ArrayAdapter(this, android.R.layout.simple_list_item_1, android.R.id.text1, values);//создаю адаптер, переменная values содержит название напитков

        listView.setAdapter(adapter);

        listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {//обработчик нажатия на элемент в листвью
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
                int itemPosition = position;
                String itemValue = (String) listView.getItemAtPosition(position);
                AlertDialog.Builder alertDialogBuilder = new AlertDialog.Builder(context);


                alertDialogBuilder.setTitle("Message:");
                alertDialogBuilder.setMessage( "Название напитка:\n" + itemValue);//здесь должен показываться состав вроде молоко, объем и т.д.
                AlertDialog alertDialog = alertDialogBuilder.create();
                alertDialog.show();//вывожу диалог на экран
            }
        });
    }
}

Answer 1

More shortly begin that throw out ListView. Forget about it like it doesn't exist. He teaches bad things, all these ArrayAdapters are evil, you can't see behind them how to do it right.
Take RecyclerView. It will seem harder to you, but it will make you do the right thing.
Get away from the string list. The list of strings is nothing, the string "espresso" has no composition. You must have a model, a POJO, that stores your data for one list item. Is it one line in your case? Great, this will be a class with one field. Then you will add one more field to the same class - id (id) of this element. By ID, you should be able to unambiguously receive both the name and the list of ingredients.
Next, when you write a custom adapter for RecyclerView, you will need to put onClickListener on the views. pressing this listener you have to throw into your interface

interface CoffeeSelectionListener {
    void onCoffeeSelected(int coffeeId);
}

This listener interface should come to your adapter from the outside, so you abstract away from a specific action. And this is good.
Put a listener on the outside, and find the list of ingredients by the ID. Show him next.
God forbid you show in AlertDialog'e. Take the DialogFragment, take your time, but do it right. Nobody uses dialogue anymore.
When you do this, you will end up with slightly better quality code. Further it will be necessary to abstract further.

Answer 2

Well, in a nutshell: Java has such a Map data structure - it stores lists in the form of a key, value.
For example:
(Americano)(Coffee, Water)
(Cappuccino)(Coffee, Milk)
Create such a dictionary. When the user clicks on a cappuccino, use the get("cappuccino") method to retrieve a list of ingredients from this map.