How can I fix the ConnectionAbortedError error?

Question

Django

I have an account login function, at first everything goes well, the data from the form reaches Django and the login occurs, but for some reason the readerect function (HttpResponseRedirect) does not work and an error appears:

Exception occurred during processing of request from ('127.0.0.1', 57962)
Traceback (most recent call last):
  File "C:\Users\drygo\AppData\Local\Programs\Python\Python39\lib\socketserver.py", line 683, in process_request_thread
    self.finish_request(request, client_address)
  File "C:\Users\drygo\AppData\Local\Programs\Python\Python39\lib\socketserver.py", line 360, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "C:\Users\drygo\AppData\Local\Programs\Python\Python39\lib\socketserver.py", line 747, in __init__
    self.handle()
  File "C:\Users\drygo\AppData\Local\Programs\Python\Python39\lib\site-packages\django\core\servers\basehttp.py", line 174, in handle
    self.handle_one_request()
  File "C:\Users\drygo\AppData\Local\Programs\Python\Python39\lib\site-packages\django\core\servers\basehttp.py", line 182, in handle_one_request
    self.raw_requestline = self.rfile.readline(65537)
  File "C:\Users\drygo\AppData\Local\Programs\Python\Python39\lib\socket.py", line 704, in readinto
    return self._sock.recv_into(b)
ConnectionAbortedError: [WinError 10053] Программа на вашем хост-компьютере разорвала установленное подключение

views.py

def log_hand(request):
    
    try:
        username = request.POST['username']
        password = request.POST['password']
        print(type(username), type(password))
        user = authenticate(username=username, password=password)
        
        if user is not None:
            if user.is_active:
                login(request, user)
                print('ok')
                return HttpResponseRedirect('/main/')
            else:
                return JsonResponse({'v': 'no'})
        else:
            return JsonResponse({'v': 'no'})
    except:
        
        return JsonResponse({'v': 'no'})

Answer 1

I can advise you to use redirect:

return redirect('/some/url/') # Адрес
ИЛИ
return redirect('name') # Название ссылки в urls.py