How can I create a zipfile.Zipfile in the folder I need?

Question

Django

I do in my application the return of all files from a folder in one archive. Everything is cool, the archive is being created, but for some reason, when downloading, it has no name, and inside there is a full path to files from empty directories. How do I create an archive file in the media/archs/ folder and how do I assign a name to the archive when downloading?

views.py

def DownloadAllFilesView(request, objId):
    if request.method == 'POST':
        project_folder = Doc.objects.filter(idProj=Project.objects.get(id=objId)).first().idProj.name.replace(' ', '_')
        path = settings.MEDIA_ROOT + '/project_%s/' % project_folder
        z_name = '%s.zip' % Project.objects.get(id=objId).name.replace(' ', '_')

        z = zipfile.ZipFile(z_name, 'w')  # Создание нового архива

        for file in os.listdir(path):
                z.write(os.path.join(path, file))  # Создание относительных путей и запись файлов в архив

        z.close()
        return FileResponse(open(z.filename, 'rb'))

Answer 1

inside there is a full path to files from empty directories.

https://docs.python.org/3/library/zipfile.html#zip...

How do I create an archive file in the media/archs/ folder

in z_name specify the absolute path to this location.

how to assign a name to an archive when downloading

you the third time to give a link to everything on the same?
PS well, let's already learn to read the docks on your own