grep - how to make an exact match?

Question

ubuntu

There is data from qm list:

100 srv1             running    16384            100.00 965
       101 srv2             running    12314            100.00 900
       1000 srv3              running    2048            100.00 85
       1001 srv4              running    2048           100.00 35
       10000 srv4              running    2048           100.00 480

Purpose: to get the third column by the number in the first. Current variant:
sudo qm list | grep 100 | awk '{print $3}'
If I do grep 100 - all will be displayed. But you only need to get one value.
Tried grep -F 100 - no change.
I tried grep -w 100 - the values ​​100 and 101 are displayed.
How to get only one line?

Answer 1

Why is grep here? awk is very good at comparing, and, unlike grep, it can work with individual fields, and not just with the whole line.
sudo qm list | awk '{ if ($1 == 100) print $3}'

Answer 2

you can use:
^ - start of line
$ - end of line
grep ^100$

Answer 3

grep just finds 100 lines elsewhere.
Write a regular expression that will look for the first 100, such as the beginning of a string, possibly spaces, and 100:

sudo qm list | grep  -P '^[ ]*100' | awk '{print $3}'

or 100 not followed by a dot

sudo qm list | grep  -P '100[^.]' | awk '{print $3}'

Answer 4

And the simplest thing is to put a space in quotation marks after what you are looking for ))
| grep "100"