Go HTML Template: how to display variable values in nested templates?

A

Anton2017-11-17 16:42:47

go

Anton, 2017-11-17 16:42:47

I use templates in Go nested one inside the other. I use variables in both templates. Values are substituted in the root template, but not in the nested template. What am I doing wrong?
Root template ( main_container.tpl ):

<!DOCTYPE html>
<html>
  <head>
    <title>{{ .Title}}</title>
  </head>
  <body>
    <header>
      <div id="logo"></div>
    </header>
    <main>
      {{template "content"}}
    </main>
  </body>
</html>

Nested template ( index.tpl ):

{{define "content"}}
<div class="categories_select">
  <ul>
    {{range .Categories}}
      <li>{{ .Name}}</li>
    {{end}}
  </ul>
</div>
{{end}}

Part of the code that parses and renders the template:

t, err := template.ParseFiles("templates/main_container.tpl", "templates/index.tpl")
    log.Println("Template: ", t.Tree)
    if err != nil {
      log.Println("Template err: ", err.Error())
    } else {
      err = t.Execute(w, templates.GetIndexData())
      if err != nil {
        log.Println("Template execute err: ", err.Error())
      }
    }

Result:

<!DOCTYPE html>
<html>
  <head>
    <title>Vitima - Главная</title>
  </head>
  <body>
    <header>
      <div id="logo"></div>
    </header>
    <main>
      
<div class="categories_select">
  <ul>
  </ul>
</div>

    </main>
  </body>
</html>

It can be seen that the value for {{ .Title}} was substituted. And the value for {{ .Name}} in the nested template was not substituted. Although, when all this was in one template, it worked like clockwork.

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1 answer(s)

A

Alexander Pavlyuk, 2017-11-17
@lanzert

You do not pass data to the nested template, you need to do this, for example:
If you want to pass only categories inside, you can do this:
But then you will need to iterate over them in a different way:

{{range .}}
    <li>{{ .Name}}</li>
{{end}}