Flask Pymongo. How to make a conclusion on 100 records?

Question

Flask

There is such a Route:

@app.route('/', methods=['GET'])
    def index():
        txt = mongo.db.base.find({}, {'title': 1, 'text': 1, '_id': 0})
        return render_template('Index.html', txt=list(txt))

The database stores 100,000 records that are displayed in html.

How to make a conclusion on 100 records? Or how to make pagination with Flask and Pymongo?