Execute cURL request from PHP?

Question

PHP

Hey!
There is such a cURL request:
curl -H Content-Type:application/json -X PUT -d 'the_value' localhost :7474/db/data/node/123/properties/foo
Actually, the problem is that the transmitted data is a string , not a JSON object... The Neo4j server doesn't like that very much.
How can I make such a request from php? No matter how I tried - error 500.
Please tell me which curl_setopt should be placed in order to make such a request?

Answer 1

Understood. First, the Neo4j server itself is very strict about incoming data. Therefore, the string had to be packed like this: '"some string"\n'
Further, the request should be made with sending the file. At least that's how it turned out, and that's enough)
$filename = 'test/tempfile'; //открываем темповый файл
$dataToPut = $_POST['dataToPut']; //Извлекаем из поста данные
$url = $_address; //урл
$fh = fopen('test/tempfile', 'w+');
if ($fh == false)
{
//echo("false");
}
fwrite($fh, $dataToPut); //Загоняем строку в файл
fseek($fh, 0);
$ch = curl_init();
curl_setopt($ch, CURLOPT_INFILE, $fh);
//curl_setopt($ch, CURLOPT_INFILESIZE, $length);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
curl_setopt($ch, CURLOPT_PUT, 4);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, Array('Content-type: application/json', 'Expect: '));
$response = curl_exec($ch);
fclose($fh);
$status = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);
echo $status;


Answer 2

As far as I understand JSON, JSON is a string and it is not an object, just like XML is a string. Maybe the problem is somewhere else? Or is your JSON not valid? Can't see server logs? I think there might be an answer

Answer 3

And, any other requests normally pass?