Even and odd elements in an array in C++?

Question

C++ / C#

There is such a problem, I wrote a code in which the elements fall down and go in ascending order. It is necessary that in those that fall there were only odd ones, and in growth - even ones.

Using a random number generator, generate an array of 20 elements. Arrange the elements of an array so that all even-numbered elements are in ascending order and odd-numbered elements in descending order

#include <iostream>
#include <cstdlib>
#include <time.h>

using namespace std;

int main()
{
  const int n=21;
  int m[n];
  srand(time(0));
  cout<<"Massiv M:\n";
  for(int i=0;i<n;i++)
  {
    m[i]=rand();
    cout<<"m["<<i<<"]= "<<m[i]<<endl;
  }
  
  
  // Рост
  int temp;
  for(int i=0;i<n;i++)
  {
    for(int j=1;j<n-i;j++)
    {
      if(m[j]<m[j-1]) { temp=m[j]; m[j]=m[j-1]; m[j-1]=temp;}
    }
  }
  cout<<"Vporyadkovanyj massib po zrostanny:\n";
  for(int i=0;i<n;i++)
  {
    cout<<m[i]<<" ";
  }
  cout<<endl;
  
  // Убивание
  for(int i=0;i<n;i++)
  {
    for(int g=1;g<n-i;g++)
    {
      if(m[g]>m[g-1]) { temp=m[g]; m[g]=m[g-1]; m[g-1]=temp;}
    }
  }

  cout<<"Vporyadkovanyj massib po spad:\n";
  for(int i=0;i<n;i++)
  {
    cout<<m[i]<<" ";
  }
  return 0;
}

Answer 1

Didn't look at the code. Fill it in with the condition that "variable" %2==0" else{It won't be even}