Error in PyCharm, does not start the bot, what should I do?

Question

Python

Here is the code:

@bot.message_handler(commands=['start'])
def start_message(message):
    bot.send_message(message.chat.id, 'Привет, я бот', reply_markup=keyboard())

@bot.message_handler(content_types=['text'])
def send_text(message):
    if message.text.lower() == 'Купить':
        bot.send_message(message.chat.id, '''Товар 1
        Товар 2
        Товар 3''')
    elif message.text.lower() == 'Рулетка':
        bot.send_message(message.chat.id, 'Ты выиграл приз!')

def keyboard(): #клавиатура купить/рулетка
    markup = types.ReplyKeyboardMarkup(one_time_keyboard=True, resize_keyboard=True)
    btn1 = types.KeyboardButton('Рулетка')
    btn2 = types.KeyboardButton('Купить')
    markup.add(btn1, btn2)

bot.polling()

First, pycharm throws this error:
C:\Users\Administrator\AppData\Local\Programs\Python\Python37-32\python.exe: can't open file 'bot.py': [Errno 2] No such file or directory
Secondly, the bot does not process @bot.message_handler(content_types=['text']) commands when I run it through the built-in IDLE, what should I do about it?

Answer 1

bot.message_handler(content_types=['text'])

if your script file is named bot.py - rename it, there should be no name conflict

Answer 2

Of course he won't work. You take the text of the message, convert it to lower case, and then compare it to the text with the first letter in upper case.
And on the first question, they wrote to you above