Django. How to load a block in a template on click?

Question

Django

These are the basics. But after going through the documentation, I didn’t remember (or maybe I didn’t know).
There is a basic template in which Block A is loaded. I need the contents of block B to be loaded into the corresponding {% block blockB %}{% endblock %} when the button is clicked, while the contents of A and all loaded resources are preserved. How to do it?
View will be like this?:

def loadBlockB(request):
        return render_to_response('loadBlockB.html')

How would calling this function look like on the JS side?

Answer 1

Need
- make a url for ajax request, for example
url(r'^/ajax/loadBlockB/$', view='loadBlockB', name='loadBlockB'),
- In js write
$('#container_id').load( '/ajax/loadBlockB/')
And that's it.
It is assumed that you are using jquery
If not, then any other way to make an ajax request