Custom routes to Sinatra (Padrino)?

Question

ruby

Greetings!
I am actively mastering the ruby ​​framework - sinatra along with padrino. The task is to organize url generation, which is often used on content sites:
site.ru/category/article-slug.html
in yii, this is solved using its own routing rules www.yiiframework.ru/doc/guide/ru/topics.url
is there a similar opportunity for sinatra?
I understand what can be done by passing two parameters to url_for article and category, but I would like it to pass only the id of the article, and the rule itself makes a selection from the database and forms the url.

Answer 1

You just need to write a view helper, something like article_url_for.
In Sinatra, this can be done something like this:

helpers do
  def article_url_for(id)
    # тут уже напишете выборку объекта из базы или кэша и формирование url
  end
end

Sinatra does not have a url generator because there are no controllers as such. Those. if you have routes in Yii like

'/<categoryName:\\w+>/<articleSlug:\\w+>' => "articles/read" 
'/<id:\\d+>' => "articles/read"

then you can write the action as

function actionRead(id = null, categoryName = null, articleSlug = null){
    if(!empty(id))
           article = Article::model()->findByPk(id)
    else
           article = Article::model()->findByAttributes(..)
}

And generate urls:

$this->createUrl('articles/read', array('categoryName' => 'Books', 'slug' => 'Another-great-book')) //сгенерирует url первого вида 
$this->createUrl('articles/read', array('id' => 123)) //сгенерирует url второго вида

In order to generate a url of the first kind by passing the id of the object, you still have to write a helper in Yii that will pull the object out of the database and generate the url in the standard way, passing the resp. options.

Answer 2

That's it, I saw - you are talking about the inheritance of "CBaseUrlRule".
No, there is no such thing in Sinatra.