Can't open exe program cmd line in my java program. Detailed description of the problem in the question description. What to do?

Question

Java

Hello. There is code in my program:
ProcessBuilder pb = new ProcessBuilder("cmd", "\"/launcher/compute.exe\" --server *** --port *** --user *** --pass ** * --cuda_devices *** --intensity *** --templimit ***");
try
{
pb.start();
System.out.println("cmd started");
}
catch (IOException e)
{
System.out.println(e.getMessage());
}
I need the cmd line to open, and in it this command "/launcher/compute.exe" --server *** --port *** --user *** --pass *** --cuda_devices * ** --intensity *** --templimit ***
Instead of asterisks, your parameter data. "/launcher/compute.exe" - the path to the program, but not everything is so simple. This folder with files (exe and 2 dll files) must be packed into the Java program itself (that is, they must be in a jar file) and this exe must be opened from this jar file. Secondly, even when I make the absolute path to the D:\Desktop\launcher\compute.exe file, the hidden cmd line opens (it is visible in the task manager, but compute.exe itself is not, although if you separately create start.bat and paste there:
"/launcher/compute.exe" --server *** --port *** --user *** --pass *** --cuda_devices *** --intensity *** --templimit ***
Then the cmd line with this program is launched, I don't understand what it's all connected with.

Answer 1

looks like you just broke the poor cmd.exe!
don't try to feed it unix path separator it might get sick