Call a function with the name of the function in a string?

Question

go

Good afternoon.
How can you call a function knowing the name of the function? Those. the string variable contains the name of this function. Is it possible?

func f(){
fmt.Println("функция вызвана")
}

func main(){
str = "f"
вызвать_функцию(str)
}

Answer 1

In general, no.
https://mikespook.com/2012/07/function-call-by-nam...

Answer 2

You can only organize it through the ass. Stifler 's dad in a nearby answer showed how. A lot of reflection in the example code and shows that this is the wrong way. Only as a last resort.
And here is a thing that does not contradict the ideology of Go - it will be with an explicit indication of types:

package main

import (
  "fmt"
)

func add(a, b int) int {
  return a + b
}

func sub(a, b int) int {
  return a - b
}

func main() {

  table:= make(map[string]func(int,int)int)
  
  table["func1"] = add
  table["func2"] = sub
  
  fmt.Println(table["func1"](5, 3))
  fmt.Println(table["func2"](5, 3))
}

Much less code, types are rigidly defined.

Answer 3

in my opinion, when in such languages ​​they try to call a function implicitly, something is wrong with the architecture of the program.
interesting to see the full picture of what it is for.