All the same, in java passes an array by reference or not?

Question

Java

Everywhere they write that java passes primitives by value, and objects by reference.
And they also write that an array is an object passed by reference.
So if it should be passed by reference then why do I have an array passed by value?

import java.util.Arrays;

public class ssulk 
{
  public static void main(String[] args)
  {
    int[][] a = new int[2][2];
    a[0][0]=1;
    a[0][1]=2;
    a[1][0]=3;
    a[1][1]=4;
    
    System.out.println("1  "+a[0][0]);
    
    a[0][0]=a[1][1];
    System.out.println("2  "+a[0][0]);
    put(a[0],a[1]);
    System.out.println("3  "+a[0][0]);
    
  }
  
  static void put(int[] a,int[] b)
  {
    System.out.println("4  "+a[0]);
    a=b;
    //a=Arrays.copyOf(b, 2);
    System.out.println("5  "+a[0]);
  }
}

here outputs
1 1
2 4
4 4
5 3
3 4
>> passes by value. so what's up?
new question on the answer:
1) so like Arrays.copyof() changes the value(!)(?) of the array, but displays the same
2) How to make it work as it should?

Answer 1

Everything worked correctly. An array is an object and is passed
by reference. But the reference is passed by value.
a=b;
here you are already manipulating copies of references inside the method.

Answer 2

Everything in Java is pass-by-value . However, if you're passing a reference, it's the value of the reference.

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