ajax(jquery) - php. passing data (variables) back and forth?

O

olinapopa2016-08-08 15:44:41

PHP

olinapopa, 2016-08-08 15:44:41

There are two files, index.php and random.php.
From index.php we send ajax data from the form to random,php. back we get html.
How can I make sure that after sending to random, some variables are sent back to the index from there?

INDEX.PHP

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
    <title></title>
    <meta http-equiv="Content-Type" content="text/html; charset=windows-1251" />
    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
    <script type="text/javascript">


        function AjaxFormRequest(result_id,form_id,url) {
            jQuery.ajax({
                url:     "random.php", //Адрес подгружаемой страницы
                type:     "POST", //Тип запроса
                dataType: "html", //Тип данных
                data: jQuery("#"+form_id).serialize(),
                success: function(response) { //Если все нормально
                    document.getElementById(result_id).innerHTML = response;
                    var serverAnwer =  '<?php echo $number;?>';
                },
                error: function(response) { //Если ошибка
                    document.getElementById(result_id).innerHTML = "Ошибка при отправке формы";
                }
            });
        }

    </script>
</head>
<body>
<div id="result_div_id">
    Поиграем?<br/>
    <br/>
    Введите число от 1 д 10.
</div>
<br/><br/>
<form method="post" action="" id="form_id">
    <input type="text" name="number"  /><br/>

    <input type="button" value="Играем!" onclick="AjaxFormRequest('result_div_id', 'form_id', 'random.php')" />
</form>

</body>
</html>
<?php

ЗДЕСЬ ПЕРЕМЕННЫЕ ИЗ RANDOM.PHP

?>

RANDOM.PHP

<?php

if(!empty($_POST['number'])) {
    $number = $_POST['number'];
    $random = rand(1, 10);
    if($number == $random) {
        echo "Выпало число: $random";
        echo "<br>Вы выиграли!";
        global $number;
        return true;
    } else {
        echo "Выпало число: $random";
        echo "<br>Проиграли";
        global $number;
        return false;
    }
}
else {echo "Не заполнили форму";}


?>

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1 answer(s)

S

Sergey ZSA, 2016-08-08
@serjikz

You can just deduce variables. Or do you need to be able to access these variables from js after they are returned from php?